The complex ppn[Au(acac)2] 1 can be obtained by reacting ppn[AuCl2] with [TI(acac)] in 1:2 molar ratio, and complex 1 reacts with compounds of the type RH in which H has some acidic character to give the corresponding [AuR2]- species; RH = CH2(CN) 2 2, CH2(CO2Me)2 3, CH 2(CN)CO2Me 4, Me3SiCCH 5, 2-SH-C 5H4N 6, AuR RH = CH2(PPh2) 2, 7, or [AuR2]+ RH = [(4-MeC6H 4)3PCH2C5H4N-2]ClO 4 8.
|Number of pages||2|
|Journal||Journal of the Chemical Society, Chemical Communications|
|Publication status||Published - 01 Dec 1992|
ASJC Scopus subject areas
- Molecular Medicine