Abstract
It is shown that if $11$, the operator $I+T$ attains its norm. A reflexive Banach space $X$ and a bounded rank one operator $T$ on
$X$ are constructed such that $\|I+T\|>1$ and $I+T$ does not attain its norm.
Original language | English |
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Pages (from-to) | 115-136 |
Number of pages | 22 |
Journal | Integral Equations and Operator Theory |
Volume | 64 |
Issue number | 1 |
Publication status | Published - May 2009 |
ASJC Scopus subject areas
- Algebra and Number Theory
- Analysis