Abstract
It is shown that if $11$, the operator $I+T$ attains its norm. A reflexive Banach space $X$ and a bounded rank one operator $T$ on
$X$ are constructed such that $\|I+T\|>1$ and $I+T$ does not attain its norm.
| Original language | English |
|---|---|
| Pages (from-to) | 115-136 |
| Number of pages | 22 |
| Journal | Integral Equations and Operator Theory |
| Volume | 64 |
| Issue number | 1 |
| Publication status | Published - May 2009 |
ASJC Scopus subject areas
- Algebra and Number Theory
- Analysis