Abstract
A bounded linear operator T on a Banach space X is called frequently hypercyclic if there exists x ∈ X such that the lower density of the set { n ∈ N : Tnx ∈ U } is positive for any non-empty open subset U of X. Bayart and Grivaux have raised a question whether there is a frequently hypercyclic operator on any separable infinite dimensional Banach space. We prove that the spectrum of a frequently hypercyclic operator has no isolated points. It follows that there are no frequently hypercyclic operators on all complex and on some real hereditarily indecomposable Banach spaces, which provides a negative answer to the above question.
Original language | English |
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Pages (from-to) | 123-134 |
Number of pages | 12 |
Journal | Proceedings of the American Mathematical Society |
Volume | 137 |
Issue number | 1 |
Early online date | 28 Aug 2008 |
DOIs | |
Publication status | Published - 02 Jan 2009 |
ASJC Scopus subject areas
- General Mathematics
- Applied Mathematics